What is the average acceleration of a train that speeds up from 9.6m/s to 12 m/s in .8 seconds?
Answers
Answered by
1
Answer: Vf-Vi/T
(12m/s-9.6m/s)/8s
=2.4/8
=0.3
Explanation:
Similar questions
Hindi,
2 months ago
English,
2 months ago
Social Sciences,
4 months ago
English,
11 months ago
Math,
11 months ago