Question

What is the average kinetic energy of 1 mole of a so2 at 300 Kelvin?

Answer 1

Answer:3741.3 J/mol

Explanation:Average kinetiic energy of 1 Mole SO2 = 3/2 nRT = (3/2) 1*8.314* 300 =3741.3 J/mol or 3741 J/mol

Answer 2

Answer:

3.7413 kJ

Explanation:

Given :

No. of moles n = 1 mole

Temperature T = 300 K

We are asked to find Avg. Kinetic energy :

We know :

Avg. K.E. = ( 3 / 2 ) n R T

Value of R = 8.314 J mol⁻¹ K⁻¹

Putting values we get :

Avg. K.E. = ( 1.5 ) × 1 × 8.314 × 300 J

Avg. K.E. = ( 1.5 ) × 2494.2 J

Avg. K.E. = 3741.3 J

Avg. K.E. =  3.7413 kJ

Hence we get required answer!