Question

what is the average of all even numbers from 1to95​

Answer 1

Step-by-step explanation:

last even no. (an)= 94

first even no. (a) =2

difference between consecutive even no.(d) =2

an = a+ (n -1)d

94 =2+(n-1)2

94 = 2 +2n -2

94 =2n

n ( total even no.) = 94/2

=47

avg = sum from 2 to 94 even no. / 47

avg = 2+4....94/47

avg= 2(1+2+3.....47)/47

avg = 2( n (n+1) ) /47 ;( sum of consecutive natural no. = n(n+1) where n is total no. of no.s )

avg =2 (47*48) /47

avg = 96