Math, asked by BookSCrazY, 11 months ago

what is the average of the first 45numbers in the series 6,13,20,27,34...…? show step by step 1)320,2)163,3)160,4)327​

Answers

Answered by akshataryan1410
8

Answer:

The answer is option 3)160

Step-by-step explanation:

Given,

Sequence:-

6,13,20,27,34.............

Clearly,

The common difference(d) = 7

No. of terms(n) = 45

So,

Average = Sum / 45

Now,

Sum = n/2[2a + (n-1)d]

= 45/2 (2*6 + 44*7)

= 45/2 (12+308)

= 45/2 (320)

= 45*160

= 7200

Now,

Average = 7200/45 = 160

Hope this helps you.

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