what is the average of the first 45numbers in the series 6,13,20,27,34...…? show step by step 1)320,2)163,3)160,4)327
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Answer:
The answer is option 3)160
Step-by-step explanation:
Given,
Sequence:-
6,13,20,27,34.............
Clearly,
The common difference(d) = 7
No. of terms(n) = 45
So,
Average = Sum / 45
Now,
Sum = n/2[2a + (n-1)d]
= 45/2 (2*6 + 44*7)
= 45/2 (12+308)
= 45/2 (320)
= 45*160
= 7200
Now,
Average = 7200/45 = 160
Hope this helps you.
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