①
What is the average of the numbers
101, 103, 105, 107, 109?
2 what is one common factor in the
expressions ?
O mntna
2 a² and a 36²
Write the product form of (1) 3xy abce
which of the following
following are pythagorean
triplet 1
10 3,4,5 ☺ 3,3,5 ④ 24, 1,26 ① 7,24,25
3.
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Answers
Answer:
average of numbers is 105
Solution :-
→ Required Average = (101 + 103 + 105 + 107 + 109)/5 = 525/5 = 105
now,
→ common factor of 2a² and a36² = 2a .
and,
→ Product of 3xy and abce = 3xy * abce = 3xyabce .
checking the triplets by using pythagoras theorem now,
→ 3² + 4² = 5²
→ 9 + 16 = 25
→ 25 = 25 . yes.
next,
→ 3² + 3² = 5²
→ 9 + 9 = 25
→ 18 ≠ 25 . no .
next,
→ 24² + 1² = 26²
→ 576 + 1 = 676
→ 577 ≠ 676 . no .
next,
→ 7² + 24² = 25²
→ 49 + 576 = 625
→ 625 = 625 . yes.
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