What is the average speed of a partical performing linear shm of amplitude over one oscillation
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The average speed of a particle performing linear S.H.M of amplitude 'a' over one oscillation is zero.
The relation of displacement of that particular particle is x(t) = a*sin wt
And the derivative of displacement with respect to time gives us the speed of the particle;
dx(t)/ dt = v(t)
v(t) =d[a*sin wt]/ dt = a*w*cos wt
v(t) = a*w*cos wt
So one oscillation the time period is one so the upper relation gives us the value zero.
The average speed of a particle performing linear S.H.M of amplitude 'a' over one oscillation is zero.
The relation of displacement of that particular particle is x(t) = a*sin wt
And the derivative of displacement with respect to time gives us the speed of the particle;
dx(t)/ dt = v(t)
v(t) =d[a*sin wt]/ dt = a*w*cos wt
v(t) = a*w*cos wt
So one oscillation the time period is one so the upper relation gives us the value zero.
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