Math, asked by attrivishal196, 7 months ago

What is the ax³+bx²+ cx+d=0​

Answers

Answered by rahularava888
0

Answer:

vvffbnjnfhbgbh

ghhjjnbgg by hh

hhhnnj

Answered by yeshwitha2936
0

Step 1: Add -bx to both sides.

ax^3+bx+c+−bx=0+−bx

ax^3+c=−bx

Step 2: Add -c to both sides.

ax^3+c+−c=−bx+−c

ax^3=−bx−c

Step 3: Divide both sides by x^3.

(ax^3) /x^3 = (−bx−c)/x^3

x3

a= (−bx−c)/x^3

Answer:

a= (−bx−c)/x^3

mark as brainlist and thanks

Similar questions