Math, asked by lordanjitvin, 1 year ago

What is the axis of symmetry of h(x)=(1)/(2 )x^(2)+3. Explain

Answers

Answered by AwesomeSoul47
6

Answer:

Hey mate here is your answer..........

(x) = - 3x^2 + 3x - 2

Explanation:

x of vertex = x of axis of symmetry:

y of vertices

y intercept: y = -2

x-intercepts -> y = 0

D = b^2 - 4ac = 9 - 24 = - 15 < 0. There are no real roots (no x-intercepts) because D < 0.

Since a < 0, the parabola opens downward. The parabola is completely below the x-axis.

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