What is the axis of symmetry of h(x)=(1)/(2 )x^(2)+3. Explain
Answers
Answered by
6
Answer:
Hey mate here is your answer..........
(x) = - 3x^2 + 3x - 2
Explanation:
x of vertex = x of axis of symmetry:
y of vertices
y intercept: y = -2
x-intercepts -> y = 0
D = b^2 - 4ac = 9 - 24 = - 15 < 0. There are no real roots (no x-intercepts) because D < 0.
Since a < 0, the parabola opens downward. The parabola is completely below the x-axis.
Similar questions