Question

What is the base edge of square pyramid of maximum size that can be carved out from the hemisphere of radius 5cm?
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Answer 1

Answer:

7.071 cm

Explanation:

diagonal of square = diameter of hemisphere

                                = 2r = 2(5)

                                = 10 cm

pythagorean theorem

a² + b² = c², c be the diagonal of the square. a & b base edge of square and  are equal.

so,

2a²=c²

a²=c²/2 = 100/2

a = √50

a = 7.071