Math, asked by simi4200, 1 year ago

What is the best approximation for (1+1/10000000)^10000000?

Answers

Answered by umasubafs
0

With good-enough scientific calculator (base change formula yields log102=ln2/ln10):

(2×106)−455=10−455(6+ln2/ln10)=10−2866.9686⋯=100.0313⋯×10−2867=1.07486⋯×10−2867.

Answered by ItzMiracle
34

Answer:

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Step-by-step explanation:

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