what is the biggest vaule of sin theata* cos theata
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Answer:
Step-by-step explanation:
f(θ)=sinθ+cosθ
=2–√(12√sinθ+12√cosθ)
=2–√(cosπ/4∗sinθ+sinπ/4∗cosθ)
=2–√(sin(π/4+θ))
As you know greatest
value of
sinθ=1
so greatest value of
f(θ)=2–√∗1=2–√
Another approach can be made by using calculus
f(θ)=sinθ+cosθ
Differentiating w.r.t θ
f‘(θ)=cosθ−sinθ
Equating it to zero we get ,
f‘(θ)= 0
cosθ−sinθ =0
cosθ=sinθ
tanθ=1
θ=π4
So greatest value will be at θ=π4 [of course check that f‘‘(θ)<0 ] i.e greatest value is f(π4)
=sinπ4+cosπ4
=12√+12√
=2–√
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