Question

What is the bond angle of F-xe-o in xeof4 . Nd what is the bond angle of F-xe-F in xef5 + molecule Tell a comparison of these bond angle in molecules.

Answer 1

Answer:

The F-Xe-F bond angle in XeF

4

is 90

0

. In XeF

4

molecule the Xe is at the centre and fluorine atoms are directed towards four corners of a square. The geometry is square pyramidal

Explanation:

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