Science, asked by gautam0796, 11 months ago

What is the bond line structure for cyclo propene?​

Answers

Answered by krishnanhsss
0

Explanation:

The triangular structure of cyclopropane requires the bond angles between carbon-carbon covalent bonds to be 60°. This is far less than the thermodynamically most stable angle of 109.5° (for bonds between atoms with sp3 hybridised orbitals) and leads to significant ring strain.

Chemical formula: C3H6

Boiling point: −33 °C (−27 °F; 240 K)

Melting point: −128 °C (−198 °F; 145 K)

Density: 1.879 g/L (1 atm, 0 °C)

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