What is the bond line structure for cyclo propene?
Answers
Answered by
0
Explanation:
The triangular structure of cyclopropane requires the bond angles between carbon-carbon covalent bonds to be 60°. This is far less than the thermodynamically most stable angle of 109.5° (for bonds between atoms with sp3 hybridised orbitals) and leads to significant ring strain.
Chemical formula: C3H6
Boiling point: −33 °C (−27 °F; 240 K)
Melting point: −128 °C (−198 °F; 145 K)
Density: 1.879 g/L (1 atm, 0 °C)
Similar questions