What is the bond order for the C22− ion? 3 0 2 1 1.5
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The order starting with the highest bond order is = C2- > C2 > C2+.
Explanation:
Given: Chemical Components
To find: Bond order
Solution:
Bond order = 1/2 (number of electrons in bonding orbitals - number of electrons in antibonding orbitals)
Therefore, Bond order of C2+ = 1/2 (5 - 2) = 3/2 = 1.5
Bond order of C2- = 1/2 (7 - 2) = 5/2 = 2.5
Bond order of C2 = 1/2 (6 - 2) = 2
The highest bond order means the highest bond energy and shortest bond length.
So, the highest bond order with the highest bond energy and the shortest bond length is found in C2-.
So, the order starting with the highest bond order is = C2- > C2 > C2+.
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