Chemistry, asked by mansimrankaur8476, 1 year ago

What is the bond order of any molecule containing equal numbers of bonding and antibonding electrons?

Answers

Answered by Shubu01
1

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☆☞ Here is ur answer ☜☆

✔✔ When bonding and antibonding character are equal, the bond order is 0 .

✔✔ So, when the number of bonding and antibonding electrons is equal, the bond order is 0 .

✔✔ The physical meaning is that the compound doesn't exist. but if there are equal numbers of each kind, then the bond order is 12(x−x)=0 , as we predicted above.

HOPE IT HELPS!

Answered by Anonymous
0

✔✔ When bonding and antibonding character are equal, the bond order is 0 .

✔✔ So, when the number of bonding and antibonding electrons is equal, the bond order is 0 .

✔✔ The physical meaning is that the compound doesn't exist. but if there are equal numbers of each kind, then the bond order is 12(x−x)=0 , as we predicted above.

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