Chemistry, asked by mehak996, 4 months ago

what is the bond order of boron​

Answers

Answered by DeathAura
2

Answer:

1/2

Bond order = 1/2 [Nb – Na] = 1/2 [6 – 4] = 1.

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The bond order of B2 molecule is:

Answered by Niranjan7262
1

Answer:

1/2

Bond order = 1/2 [Nb – Na] = 1/2 [6 – 4] = 1.

...

The bond order of B2 molecule is:1/2

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