what is the bond order of boron
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Answered by
2
Answer:
1/2
Bond order = 1/2 [Nb – Na] = 1/2 [6 – 4] = 1.
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The bond order of B2 molecule is:
Answered by
1
Answer:
1/2
Bond order = 1/2 [Nb – Na] = 1/2 [6 – 4] = 1.
...
The bond order of B2 molecule is:1/2
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