What is the bond order of N2+?
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Answered by
1
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bond order for N2+ is 2.5
I hope this is helpful ♥️
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bond order for N2+ is 2.5
I hope this is helpful ♥️
MARK ME AS BRAINLIEST ⭐⭐⭐
Answered by
4
✔️✔️There are 14 electrons in N2 molecule.
so we can arrange the electrons like :-
⭕️(σ1s)^2 (σ*1s)^2 (σ2s)^2 (σ*2s)^2 (π2px ^2 = π2py 2) (σ2p z )^2
✔️✔️here bond order is
= (Nb-Na) / 2
= (10-4) / 2
=6/2
= 3
⭕️In N2+, there is 1 electron less in bonding orbital than if we compare it to electrons in N2.
⭕️ So there will be 1 electron less in the σ2p z orbital.
⭕️Therefore the arrangement of electrons will be :-
(σ1s)^2 (σ*1s)^2 (σ2s)^2 (σ*2s)^2 (Π2px 2 = π2py 2)(σ2p z )^1
✔️✔️So the bond order in N2+ ion will be
= (9-4) / 2 = 2.5
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so we can arrange the electrons like :-
⭕️(σ1s)^2 (σ*1s)^2 (σ2s)^2 (σ*2s)^2 (π2px ^2 = π2py 2) (σ2p z )^2
✔️✔️here bond order is
= (Nb-Na) / 2
= (10-4) / 2
=6/2
= 3
⭕️In N2+, there is 1 electron less in bonding orbital than if we compare it to electrons in N2.
⭕️ So there will be 1 electron less in the σ2p z orbital.
⭕️Therefore the arrangement of electrons will be :-
(σ1s)^2 (σ*1s)^2 (σ2s)^2 (σ*2s)^2 (Π2px 2 = π2py 2)(σ2p z )^1
✔️✔️So the bond order in N2+ ion will be
= (9-4) / 2 = 2.5
pratik7555:
thnax
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