Chemistry, asked by pratik7555, 1 year ago

What is the bond order of N2+?

Answers

Answered by sanjeetmanhas01
1
Hello there! ♥️

bond order for N2+ is 2.5

I hope this is helpful ♥️
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Answered by NidhraNair
4
✔️✔️There are 14 electrons in N2 molecule.

so we can arrange the electrons like :-

⭕️(σ1s)^2 (σ*1s)^2 (σ2s)^2 (σ*2s)^2 (π2px ^2 = π2py 2) (σ2p z )^2


✔️✔️here bond order is
= (Nb-Na) / 2
= (10-4) / 2
=6/2
= 3

⭕️In N2+, there is 1 electron less in bonding orbital than if we compare it to electrons in N2.

⭕️ So there will be 1 electron less in the σ2p z orbital.  

⭕️Therefore the arrangement of electrons will be :-

(σ1s)^2 (σ*1s)^2 (σ2s)^2 (σ*2s)^2 (Π2px 2 = π2py 2)(σ2p z )^1

✔️✔️So the bond order in N2+ ion will be

= (9-4) / 2 = 2.5

\huge\bf{\underline{\mathfrak{thank \:  you :)}}}



pratik7555: thnax
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