Question

what is the bond order of N2+ ion​

Answer 1

✫Answer✫

Total number of electrons present in N$_2$+ is 2 x 7 - 1 = 13

So, by Molecular orbital theory, we can write the configuration as:

σ1s$_2$  σ*1s$_2$  σ2s$_2$ σ*2s$_2$  π2px$_2$  π2py$_2$  σ2pz$_1$

By formula, we know than:

Bond order =$\frac{b-a}{2}$

Here, b is the number of bonding electrons.

b = 2+2+2+2+1 = 9

a is the number of antibonding electron.

a = 2+2 = 4

✫✫✫  Hence, bond order will be:

½(9-4) = 2.5  ✫✫✫

Answer 2

ANSWER

2.5

2.5Discover the world's research

2.5Discover the world's researchthe N2+ molecule). That is, the bond order for N2+ is 2.5.

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