Math, asked by moishaambusht73, 5 hours ago

What is the break-even point ? (Zero profit point is called break-even)

(a) 10 barrels (b) 30 barrels (c) 20 barrels (d) 100 barrels

(iii) What is the profit/loss if 175 barrels are produced

(a) Profit 266200 (b) Loss 266200

(c) Profit 240250 (d) Loss 240250

(iv) What is the profit/loss if 400 barrels are produced

(a) Profit 266200​

Answers

Answered by paari2003
6

Answer:

Given :  A barrel manufacturer can produce up to  300 barrels per day. The profit made  from the sale of these barrels can be modelled by the function

p(x) = – 10x² + 3500 x – 66000, where p(x) is the profit in

rupees and x is the number of barrels made and sold.

To Find : degree of the above polynomial

When no barrels are produce, what is the loss

What is the profit/loss if 175 barrels are produced

What are the factors of the given polynomial

Solution:

p(x) = – 10x² + 3500 x – 66000

Degree  = 2

When no barrels are produce, x = 0

=>  p(0) = 0 + 0 – 66000 = - 66000

-ve sign means Loss

Loss = 66000

175 barrels are produced

=> p(175) = – 10(175)² + 3500 (175) – 66000

= 2,40,250

+Ve sign means profit

Profit 240250

– 10x² + 3500 x – 66000

= - 10(x²  - 350x  + 6600)

= -10(x² - 330x - 20x + 6600)

= -10(x - 330)(x - 20)

(x - 330)(x - 20)  are factors

Similar questions