Question

What is the % by volume of ozone in an ozonised sample if the rate of diffusion of the sample is .9 times than that of oxygen

Answer 1

Answer:

0.0378 percent is the answer

Answer 2

Molar mass of ozonized gas =

0.98

32

=33.65g/mol.

Let x be the mole fraction of O

2

and 1−x be the mole fraction of ozone.

∴ x(32)+(1−x)48=33.65

x=14.35/16=0.896

% of O

3

=(1−x)×100=(1−0.896)×100=10.4%