Chemistry, asked by lakshmankittu2003, 6 months ago

What is the Cell Potential of the electrochemical cell in Which the cell reaction is: Pb2+ + Cd → Pb + Cd2+ ; Given that Eocell = 0.377 volts, temperature = 25oC, [Cd2+] = 0.03M, and [Pb2+] = 0.2M.

Answers

Answered by baghelrishabh154
0

Answer:

Given Zn∣Zn

2+

(0.001M)∣∣Cu

2+

(0.1M)∣Cu

Overall cell reaction:

Zn⟶Zn

2+

+2e

Cu

2+

+2e

⟶Cu

Zn+Cu

2+

⟶Zn

2+

+Cu

E

cell

o

=standard reduction potential of cathode + standard oxidation potential of anode

E

cell

o

=0.34 to 0.76 V

E

cell

o

=1.1 V

K

C

=

[Cu

2+

]

[Zn

2+

]

=

10

−1

10

−3

=10

−2

EMF of the cell at any electrode concentration is:

E=E

o

n

0.059

log(K

C

)=1.1−

2

0.059

log(10

−2

)=1.1−

2

0.059

×(2)=1.1−0.059=1.041V

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