What is the center of the circle given by the equation (x - 2)2 + (y + 4)2 = 6? A.(2, -4) B.(-2, 4) C.(2, 4) D.(-2, -4)
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A.(2,-4)
using the standard equation of circle (x-h)^2 + (y-k)^2 = r^2
where r^2 = 6 and then h and k is as i mentioned above!!
using the standard equation of circle (x-h)^2 + (y-k)^2 = r^2
where r^2 = 6 and then h and k is as i mentioned above!!
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