What is the center-radius of (5,-2)
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Step-by-step explanation:
If you end up with an equation like (x + 4)2 + (y + 5)2 = 5, you have to keep straight that h and k are subtracted in the center-radius form, so you really have (x – (–4))2 + (y – (–5))2 = 5. That is, the center is at the point (–4, –5), not at (4, 5
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