what is the centre of gravity of a semi circle is at a perpendicular distance from its centre
1.3r/4pie
2.4r/3pie
3.8r/3
4.3r/8
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The center of gravity of a semi circle is at a perpendicular distance from its center is 2. 4r/3π
Step-by-step explanation:
Now, the point (x, y) is:
x = ∫x.dA/A
And
y = ∫y.dA/A = ∫(y/2 (y.dx))/(1/2 πR²)
y = ∫ y² dx/πR²
y = 2[R³ - R³/2]/πR²
y = 2(2/3 R³)/πR²
∴ y = 4R/3π
The perpendicular distance from center of semicircle is y axis. Thus, the center of gravity is at 4R/3π from center.
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