Question

what is the chance of geting the sum of at least 7when two dice are rolled togather?​

Answer 1

Answer:

Total no. of sample space-36

Total no. of favourable outcomes-6

(1+6, 2+5, 3+4, 4+3, 5+2, 6+1)

Probality=1/6

Answer 2

$\huge\red{\underline{\overline{\mathbb{ληsωεя:-}}}}$

The total number of possible outcomes is 36 and there are 21 possible "winners." Therefore, the probability of winning is 21 out of 36 or 21 divided by 36. If you do the division, the answer is 0.58333333 or you have a 58.333333% chance that on a single roll you will get a total of 7 or greater.

$\huge\blue{follow=follow}$