Math, asked by sovi7919, 1 year ago

What is the chance of getting a sum of 10 in a single throw of two dice together?

Answers

Answered by dishabucha
1

Answer:

Step-by-step explanation:

Favorable outcomes = 3 [ (4,6) , (5,5) , (6,4)

Total outcomes = 36

Pe = 3/36 = 1÷12

Hope it works


dishabucha: Plz mark as brainliest
Answered by shadowsabers03
0

Two dice are thrown simultaneously. Thus the total no. of outcomes is 6² = 36.

Now we have to find the no. of outcomes in which the sum of the two numbers in the dice being 10.

⇒ According to 10=1+9, 1 can't be drawn in any dice, because there's no 9 in a dice.

⇒ According to 10=2+8, thus neither can be 2 as there's no 8.

⇒ According to 10=3+7, thus neither can be 2 as there's no 7.

⇒ According to 10=4+6, 4 and 6 can be drawn simultaneously.

  • 4 can be drawn in first dice and 6 can be in the other.   →   (1)
  • 6 can be drawn in first dice and 4 can be in the other.   →   (2)

⇒ According to 10=5+5,  5 can be drawn in both dices simultaneously.   →   (3)

Thus the no. of favourable outcomes = 3

Hence,  probability = 3/36 = ''1/12''.

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