What is the chance of getting a sum of 10 in a single throw of two dice together?
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Answer:
Step-by-step explanation:
Favorable outcomes = 3 [ (4,6) , (5,5) , (6,4)
Total outcomes = 36
Pe = 3/36 = 1÷12
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Two dice are thrown simultaneously. Thus the total no. of outcomes is 6² = 36.
Now we have to find the no. of outcomes in which the sum of the two numbers in the dice being 10.
⇒ According to 10=1+9, 1 can't be drawn in any dice, because there's no 9 in a dice.
⇒ According to 10=2+8, thus neither can be 2 as there's no 8.
⇒ According to 10=3+7, thus neither can be 2 as there's no 7.
⇒ According to 10=4+6, 4 and 6 can be drawn simultaneously.
- 4 can be drawn in first dice and 6 can be in the other. → (1)
- 6 can be drawn in first dice and 4 can be in the other. → (2)
⇒ According to 10=5+5, 5 can be drawn in both dices simultaneously. → (3)
Thus the no. of favourable outcomes = 3
Hence, probability = 3/36 = ''1/12''.
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