Question

what is the chance of getting atleast one defective item if 3 items are drawn randomly from a lot containing 6 items of which 2 are defective item?​

Answer 1

$\huge\bold\red{HELLO!}$

n = 3 ; number of defective = 2 ; number of not defective = 4

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P(at least one defective) = 1 - P(3 not defective)

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= 1 - 4C36C3

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= 1 - 4/20

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= 1 - 1/5

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= 4/5

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