Question

what is the chance of throwing at least 7 in single cast with 2 dice​

Answer 1

Total number of outcomes = 36

Possibilities of getting 7 = (1,6)(2,5)(3,4)(4,3)(5,2)(6,1)

Hence total number of favorable outcome = 6

Therefore,

Probability of getting 7 in the cast of 2 dice

= Total number of favorable outcome/Total outcome

= 6/36 = 1/6

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