Question

What is the change in internal energy if 1 kj of heat is released from the system and 4 kg of work is done on the system

Answer 1

Answer:

The change will be of 3KJ.

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Answer 2

Change in internal energy is 3 kj.

The question will be solved with the help of first law of thermodynamics, which states that energy is neither created nor destroyed.

It is given by the equation -

∆U = Q + W

∆U denotes change in internal energy, q denotes heat and w is for work done.

Given in the question,

Work is done on the system, hence work done will be +4 kj.

Heat is released from the system hence Q will be -1 kj.

Now keeping the values in equation to get change in internal energy-

∆U = +4 + (-1)

∆U = 4 - 1

∆U = 3 kj.

Hence, change in internal energy is 3 kj.