What is the change in internal energy of 2 mole of air (C =21
X 104 J/mole °C), if its temperature changes from 10 °C to 20 °C
Select one
a. 540 kj
b. 840 )
0 C420
d. 1050 kJ
Answers
Sorry dear, I have no idea on this topic
We have to find the change in internal energy of 2 mole of air (Cv = 2.1 × 10⁴ J/mol/°C) , if its temperature change from 10°C to 20°C.
solution : change in internal energy, ∆U = heat at constant volume = nCv∆T
here no of moles = n = 2
molar heat capacity at constant volume, Cv = 2.1 × 10⁴ J/mol/°C
change in temperature, ∆T = 20°C - 10°C = 10°C
so, change in internal energy , ∆U = 2 mol × 2.1 × 10⁴ J/mol/°C × 10°C
= 4.2 × 10⁵ J
= 420 × 10³ J = 420 kJ
Therefore the change in internal energy is 420 kJ.
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