Question

What is the change in momentum of a car weighing 1200 kg when its speed increases from 36 km/h to 72 km/h uniformly?

Answer 1

The change of momentum of the car is equal to

Explanation:

Given,

• The initial speed of the car is 36 kilometre per hour or 10m/sec

• The final speed of the car is 72 kilometre per hour or 20 metre per second

• The mass of the car is equal to 1200 kg

So change in momentum= mv2 -mv1 =m(v2-v1)

• = 1200( 20-10) = 12,000 kg m /sec

• the rate of change of linear momentum is known as the force which acts on a body according to the second law of Newton

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Answer 2

Given:

Initial speed, v1 = 36 km/hr = 10 m/s

Final speed, v2 = 72 km/hr = 20 m/s

Mass of car, m = 1200 kg

To Find:

The change in momentum of the car.

Calculation:

- Initial Momentum, p1 = mv1

⇒ p1 = 1200 × 10 = 12000 kgm/s

- Final Momentum, p2 = mv2

⇒ p2 = 1200 × 20 = 24000 kgm/s

- Change in momentum = Final momentum - Initial momentum

⇒ Δp = p2 - p1

⇒ Δp = 24000 - 12000

⇒ Δp = 12000 kgm/s

- So, the change in momentum of the car is 12000 kg m/s.