Question

What is the change in momentum of a car weighing 1500 kg when its speed increases from 36 km/h to 72 km/h uniformly?plz do not skip any step show all the step clearly.

Answer 1

GIVEN,
         MASS, m                    = 1500 kg
         INITIAL VELOCITY,u  = 36 km/h = 36*5/18 = 10 m/s
         FINAL VELOCITY ,v   = 72 km/h =  72*5/18=  20 m/s
          FORMULA : 
                  CHANGE IN MOMENTUM,p = mv - mu
                                1500*20 - 1500*10
                                 30000 - 15000
                                   = 15000 kg m/s 
                                  

Answer 2

Answer:

The change in momentum of a car is 15000 kgms⁻¹.

Explanation:

• Momentum is the quantity of motion multiplied by the velocity at which it travels. p = mv
• According to Isaac Newton's second law of motion, the time rate of momentum shift is proportional to the force applied on the particle.
• There is no momentum change if a body experiences no external forces at all because the rate of momentum change is also zero.

Given:

Initial velocity $u=36kmh^{-1}$

                       $u=36$  × $\frac{1000}{3600}$

                       $u=36$  × $\frac{5}{18}ms^{-1}$

                       $u=10ms^{-1}$

Final velocity, $v=72kmh^{-1}$

                       $v=72$  × $\frac{1000}{3600}$

                       $v=72$  ×  $\frac{5}{18}ms^{-1}$

                       $v=20ms^{-1}$

Therefore, change of momentum = mv - mu

Change of momentum = m(v - u)

Change of momentum = 1500kg (20 - 10) ms⁻¹

Change of momentum = 1500kg × 10 ms⁻¹

Change of momentum = 15000 kgms⁻¹

∴The change in momentum of a car is 15000 kgms⁻¹.

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