Question

what is the change in momentum of a car weighing 1500 lg when its speed increases from 36 km per hour to 72 km per hour uniformly​

Answer 1

Answer:

Momentum of car at speed 36km/h=10m/s=m×10

=1500×10

=15000kg m/s

Momentom of car at speed 72km/h=20m/s=m×20

=1500×20

=30000kg m/s

Momentom change=30000−15000=15000kg m/s

:)

Answer 2

Answer:

m=1500kg  

u=36km/h

v=72km/h

u= 36x5/18=10 m/s

v=72x5/18=20m/s

change in momentum =m(v-u)  

                                     =1500x(20-10)

                                     =1500x10  

                                     =15000.

Explanation:

Weight is equals to 1500 kg initial velocity is equals to 36 kilometre per hour we have to change it into metre per second so we multiply it by 5/18 and final velocity is equals to 72 km per hour we have to change it also in metre per second so we multiply again it by 5/18 then we will get are final and initial velocity in metre per second then we know that change in momentum is m(v-u) so we put the weight and initial and final velocity of the car in this equation and then we have to solve it after solving we get the answer 15000.

HOPE YOU UNDERSTOOD.............

THANK YOU.