What is the change in momentum of a car win 1500 kg when its speed increase from 36 km per hour 72 km per hour uniformly
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Answered by
4
Momentum=mass x velocity
In 1st case:
Mass=1500kg
Velocity=36km/hr
p= m x v ( p=momentum) p=1500x 36 (m= mass)
p=54000kgkm/hr (v= velocity)
2nd case:
Mass=1500 kg
Velocity= 72km/hr
p=m x v
p= 1500x72
p= 108000kgkm/hr
Therefore, difference in momentum=18000-54000
=54000kmkg/hr
In 1st case:
Mass=1500kg
Velocity=36km/hr
p= m x v ( p=momentum) p=1500x 36 (m= mass)
p=54000kgkm/hr (v= velocity)
2nd case:
Mass=1500 kg
Velocity= 72km/hr
p=m x v
p= 1500x72
p= 108000kgkm/hr
Therefore, difference in momentum=18000-54000
=54000kmkg/hr
Answered by
1
Answer:
we know momentum (p)= mv
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First, lets convert the speeds into m/s since we need to write with si unit (kgm/s).
36km/hr = 36 x 5/18 = 10m/s = u (initial velocity)
72km/hr = 72 x 5 /18 = 20m/s = v (final velocity)
now, p₁ = mu = 1500kg x 10 m/s = 15000kgm/s
also, p₂ = mv = 1500kg x 20m/s = 30000kgm/s
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now, change in momentum = p₂-p₁ = (30000-15000)kgm/s = 15000kgm/s
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hope it helps. . .
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