What is the change in momentum of a ka waiting 1500 kg when its speed increases from 36 to metre per hour to 72 kilometre per hour uniformly
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change in momentum = ∆P = P2-P1
V1 = 36km/h = 36000m/3600s
= 10 m/s
V2 = 72km/h=
72000/3600
= 20m/s
P1 = mv1 = 1500×10
P2 = mv2 =1500×20
P2-P1 = 1500×20 - (1500×10)
= 1500( 20-10)
= 1500×10
= 15000 kg .m/ s
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