What is the change in momentum of the body, if the K.E increases by 25 time
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Kinetic energy of the body is
K=2mp2∴K∝p2
When the momentum of a body is increased by 25%, its momentum will become
p′=p+10025p=100125p=45p
∴KK′=p2p′2=(45)2=1625 or K′=1625K
Percentage increase in the kinetic energy of the body
=KK′−K×100=K(25/16)K−K×100=169×100=56%.
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