what is the change in oxidation number in copper in the reaction below cu2s(s)+o2(g)_2cu(s)+so2(g)
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Copper goes from +1 oxidation state to +2 oxidation state.
In Cu2S, One copper atom gives 1 electron. So oxidation no. = 1
In CuS, one copper atom gives 2 electrons to sulphur.
So, oxidation no. = 2
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