What is the change in oxidation number of fluorine in the following reaction? 2H₂O +2F₂4HF +0₂
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Answer:
opt c
Explanation:
in f2 it shows 0 oxidation state Anson Hf it shows minus 1 state
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Redox reaction is the reaction in which oxidation and reduction reaction both takes place.
Explanation:
In this reaction
2 H₂O +2F₂ → 4HF+O₂
Oxidation number of F in F₂ is 0
Oxidation number of F in HF is -1
In this reaction Oxidation number of F decreases from 0 to -1 in HF
Here oxidation and reductio both reaction takes place so
2 H₂O +2F₂ → 4HF+O₂ is a REDOX REACTION
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