Question

what is the change in oxydation number of carbon in the following reaction ? CH4 + 4cl2 gives rises ccl4 + 4Hcl​

Answer 1

Answer:

-4 to +4

Explanation:

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Answer 2

Answer:

• Oxidation number of H = 1
• Oxidation number of Cl = -1

In neutral compounds, the sum of the oxidation numbers of all the atoms is zero.

• Oxidation number of carbon in CH₄:

• Let oxidation number of C = x

$\footnotesize \longrightarrow x + 1 \times 4 = 0 \\ \\ \longrightarrow \bf x = - 4$

• Oxidation number of carbon in CCl₄:

• Let oxidation number of C = x

$\footnotesize \longrightarrow x + ( - 1) \times 4 = 0 \\ \\ \longrightarrow x - 4 = 0 \\ \\ \longrightarrow \bf x = 4$

The change in oxidation number of carbon is from -4 to +4.