Math, asked by jagruthi194, 15 days ago

What is the change in the entropy of 2.0 kg of H2O molecules when transform at a constant pressure of 1 atm from water at 100˚C to steam at the same temperature?

Answers

Answered by BruceEl
0

First of all, it increases (as gas molecules are more disordered so have higher entropy but be mindful as steam isn't gas, just closer and with higher energy ) so your answer will be positive.

Step-by-step explanation:

The nth term formula goes by :if a system has x times different environments and y times particles, the entropy is y^x that's for a small number of particles. You can't use that here.

Okay, sorry, listen here. You're going to need two formulas :

a) the formula for gibbs free energy (Gibbs free energy as it relates enthalpy change to entropy change) which is ==> GibbsFE change= Enthalpy change - Entropy change×temperature

b) The molar gas formula PV=nRT

c) find the molecular formula of H2O which will be 16+2= 18

d) the formula for entropy change which is :Entropy change= Reversible energy transfered \Kelvin temperature

So 2.0kg x 1000= 2000 grams

2000\18 will give you the number of moles.

Anyway what I'm telling you is based on the A level qualification, so it might not be more into depth. I've got a whole lot of math to learn rn so sorry i couldn't finish. Any of you here that could help me with math?

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