What is the change in velocity in the above question?
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Therefore, change in velocity is 2usinα in downward direction.
Explanation:
Correct statement:
What is the average velocity of a particle projected from ground with speed u at an angle α with horizontal over a time interval from beginning till it strikes the ground again?
What is the change in velocity in the above question?
Solution:
Δv = vf − vi
Δv = (ucosαiˆ − usinαjˆ) − (ucosαiˆ + usinαjˆ)
Δv = (−2usinα)jˆ
Therefore, change in velocity is 2usinα in downward direction.
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