Question

What is the change in velocity when a force of 10 Newton acts on a body of mass 2 kg for 10 seconds

Answer 1

Answer:

50m/s

Explanation:

f=10n

mass=2kg

t=10s

u=0

accelaration=force/mass

a=10/2

a=5

v=u+at

v=0+5*10

v=50m/s

Answer 2

Answer:

50 m/s

Explanation:

★ Given :

• Force : 10 N

• Mass : 2 Kg

• Time : 10 sec

Formula : F = $\dfrac{m(v-u)}{T}$

As we know that force is equal to dp/dt ( Rate of change of momentum )

→ 10 = $\dfrac{2(v-u)}{10}$

→ v-u ( ∆v ) = 50 m/s