Question

What is the channel capacity for a teleprinter with 300hz bandwidth and snr 3db where the noise is white thermal noise?

Answer 1

Answer:

From the given details we know,B (Bandwidth) = 300 Hz,SNRdb(Signal-to-noise ratio decibel) = 3 dB.Suppose, C = Channel capacity and SNR = signal-to-noise ratio.Now using decibel formula,SNRdb= 10 * log (SNR)That means,3 = 10 * log (SNR)SNR = log-1 0.3SNR = 100.3SNR = 1.995Hence, signal-to-noise ration (SNR) = 1.995Now using Shannon’s equation,C = B * log2(1+SNR)C = 300 * log2(1+1.995)C = 300 * log2(2.995)C = 474.76Therefore, the channel capacity for teleprinter channel is 474.76 bits per second.

Explanation:

Answer 2

The channel capacity for a teleprinter is 600 bps.

Given:

Bandwidth (B) = 300 Hz

Signal to Noise Ratio (SNR) = 3 dB

To Find:

The Channel Capacity of a Teleprinter.

Solution:

Channel capacity is the maximum rate at which the information can be transmitted through a channel. Its measuring unit is bits per second.

For Finding the Channel Capacity,

Channel capacity can easily be calculated by Shannon's equation.

The Equation is,

                    $Channel~Capacity = B~*~log(1+SNR)$

Now by inserting the given values,

                    $Channel~Capacity = 300~*~log(1+3)\\Channel~Capacity = 300~*~log(4)\\Channel~Capacity =300~*~2\\Channel~Capacity =600~bps$

The capacity of the channel comes to be 600 bits per second.