What is the coefficient of mean deviation for the following distribution of height?
Take deviation from AM.
Height in inches:
60-62
63-65
66-68
69-71
72-74
No. of students:
5
22
28
17
3
Answers
Step-by-step explanation:
Given What is the coefficient of mean deviation for the following distribution of height?
So we need to find the coefficient of mean deviation.
Height number of students(f) M.V (X) f(x) d = (x – A) f(d)
60 – 62 5 61 305 61 – 67 = 6 30
63 – 65 22 64 1408 64 – 67 = 3 66
66 – 68 28 67 1876 67 – 67 = 0 0
69 – 71 17 70 1190 70 – 67 = 3 51
72 – 74 3 73 219 73 – 67 = 6 18
∑f = 75 ∑f(x) = 4998 ∑f(d) = 165
Now X bar = ∑f(x) / ∑f
= 4998 / 75
= 66.64
Mean deviation = ∑f(d) / ∑f
= 165 / 75
= 2.2
Co-efficient of mean deviation = Mean deviation / X bar
= 2.2 / 66.64
= 0.03
Reference link will be
https://brainly.in/question/8855607
Answer:
THE A AND B OPTIONS ARE WRONG OPTION A SHOULD BE 2.50 AND OPTION B SHOULD BE 2.31
Step-by-step explanation:
