What is the coefficient of x^5 y^7 in the expansion of (x-2y)^12?
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Answer:
Answer = 0
Explanation:
0(x⁵) =0
0(y⁷)= 0
Because (x-2y)¹² = 0(x⁵)+0(y⁷)+ (x-2y)¹²
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