What is the coefficient of x in the expression 1 + x + xz? *
1 point
a) z
(b) 1 + z
(c) 1
(d) 1 + x.
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1
Answer:
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a(y+z)=x,b(z+x)=y,c(x+y)=z
⇒a=
y+z
x
;b=
z+x
y
;c=
x+y
z
Now, (1+a)
−1
+(1+b)
−1
+(1+c)
−1
=
1+a
1
+
1+b
1
+
1+c
1
=
1+
y+z
x
1
+
1+
z+x
y
1
+
1+
x+y
z
1
=
y+z+x
y+z
+
z+x+y
z+x
+
x+y+z
x+y
=
y+z+x
2(x+y+z)
=2
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