Question

what is the common deference of an A.p in which a18-a14=32​

Answer 1

Step-by-step explanation:

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Let the common difference of an A.P. be d.

Then,

a18=a1+17×d

a14=a1+13×d

Solving the two equations, 

a18−a14=a1+17d−a1−13d

⇒a18−a14=4d

Substituting 4d=32,

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⇒d=8✅

Answer 2

Step-by-step explanation:

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Let the common difference of an A.P. be d.

Then,

a18=a1+17×d

a14=a1+13×d

Solving the two equations,

a18−a14=a1+17d−a1−13d

⇒a18−a14=4d

Substituting 4d=32,

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⇒d=8✅