Question

What is the common difference of an ap in which a/18-a/14=32 .

Answer 1

Answer:8

Step-by-step explanation:

a18-a14=32

a+17d-(a+13d) =32

a+17d-a-13d=32

4d=32(a and -a gets cut)

d=32/4

d=8

Hope it helps you

Answer 2

Answer:

32 / (18-14) = 32 / 4 = 8

Step-by-step explanation:

In an AP, each step in the sequence adds the same amount (the common difference).  Calling this common difference d (the thing we need to work out), we add the value d four times as we progress from a_14 to a_18:

a_15 = a_14 + d

a_16 = a_15 + d = a_14 + 2d

a_17 = a_16 + d = a_14 + 3d

a_18 = a_17 + d = a_14 + 4d

Since we're told that a_18 - a_14 is 32, and what we've added to a_14 to get to a_18 is 4d, it follows that the common difference is d = 32/4 = 8.