what is the common difference of an AP in which a12-a18=24
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Answer:
Let the common difference of an A.P. be d.
Then,
a
18
=a
1
+17×d
a
14
=a
1
+13×d
Solving the two equations,
a
18
−a
14
=a
1
+17d−a
1
−13d
⇒a
18
−a
14
=4d
Substituting 4d=32,
⇒d=8
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