Question

what is the common difference of an ap series -1/2,-1/2,-1/2
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Answer 1

Your Answer:

Given:-

$a_1 = -1/2\\\\ a_2 = -1/2 \\\\ a_3= -1/2$

Here 'a' refers to terms

To Find:-

Common difference(d)

Solution:-

Common Difference = second term - first term

So,

$d= a_2 - a_1 \\\\ \Rightarrow d = -1/2 - (-1/2) \\\\ \Rightarrow d = 0$

So, common difference is Zero.

Answer 2

◈ Given :-

• Terms of an AP :- -½, -½, -½.

◈ To Find :-

• Difference Of An AP Series.

◈ Solution :-

We know that,

Difference = Second Term - First Term.

So,

➝ Difference = -1/2 -( -1/2).

➝ Difference = -1/2 + 1/2.

➝ Difference = 0.

Hence, Common Difference = 0.